Adam has some green stickers and blue stickers.
If 320 green stickers are removed, 80% of the stickers will be blue stickers.
If 195 green stickers are removed, 30% of the stickers will be blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
3 u + 320 |
12 u |
28 u + 195 |
12 u |
Change |
- 320 |
No change |
- 195 |
No change |
After |
1x3 = 3 u |
4x3 = 12 u |
7x4 = 28 u |
3x4 = 12 u |
(a)
80% =
80100 =
4530% =
30100 =
310Scenario 1 Fraction of the stickers that are green in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
310 =
710 The number of blue stickers remains unchanged in both scenarios.
LCM of 4 and 3 = 12
3 u + 320 = 28 u + 195
28 u - 3 u = 320 - 195
25 u = 125
1 u = 125 ÷ 25 = 5
Number of green stickers
= 3 u + 320
= 3 x 5 + 320
= 15 + 320
= 335
(b)
Number of blue stickers
= 12 u
= 12 x 5
= 60
Answer(s): (a) 335; (b) 60