Adam has some blue stickers and green stickers.
If 291 blue stickers are removed, 90% of the stickers will be green stickers.
If 141 blue stickers are removed, 40% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
2 u + 291 |
18 u |
27 u + 141 |
18 u |
Change |
- 291 |
No change |
- 141 |
No change |
After |
1x2 = 2 u |
9x2 = 18 u |
3x9 = 27 u |
2x9 = 18 u |
(a)
90% =
90100 =
91040% =
40100 =
25Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
910 =
110 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
25 =
35 The number of green stickers remains unchanged in both scenarios.
LCM of 9 and 2 = 18
2 u + 291 = 27 u + 141
27 u - 2 u = 291 - 141
25 u = 150
1 u = 150 ÷ 25 = 6
Number of blue stickers
= 2 u + 291
= 2 x 6 + 291
= 12 + 291
= 303
(b)
Number of green stickers
= 18 u
= 18 x 6
= 108
Answer(s): (a) 303; (b) 108