Adam has some blue stickers and green stickers.
If 400 blue stickers are removed, 80% of the stickers will be green stickers.
If 175 blue stickers are removed, 20% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 400 |
4 u |
16 u + 175 |
4 u |
Change |
- 400 |
No change |
- 175 |
No change |
After |
1x1 = 1 u |
4x1 = 4 u |
4x4 = 16 u |
1x4 = 4 u |
(a)
80% =
80100 =
4520% =
20100 =
15Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
15 =
45 The number of green stickers remains unchanged in both scenarios.
LCM of 4 and 1 = 4
1 u + 400 = 16 u + 175
16 u - 1 u = 400 - 175
15 u = 225
1 u = 225 ÷ 15 = 15
Number of blue stickers
= 1 u + 400
= 1 x 15 + 400
= 15 + 400
= 415
(b)
Number of green stickers
= 4 u
= 4 x 15
= 60
Answer(s): (a) 415; (b) 60