Adam has some blue stickers and green stickers.
If 320 blue stickers are removed, 80% of the stickers will be green stickers.
If 144 blue stickers are removed, 25% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 320 |
4 u |
12 u + 144 |
4 u |
Change |
- 320 |
No change |
- 144 |
No change |
After |
1x1 = 1 u |
4x1 = 4 u |
3x4 = 12 u |
1x4 = 4 u |
(a)
80% =
80100 =
4525% =
25100 =
14Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
14 =
34 The number of green stickers remains unchanged in both scenarios.
LCM of 4 and 1 = 4
1 u + 320 = 12 u + 144
12 u - 1 u = 320 - 144
11 u = 176
1 u = 176 ÷ 11 = 16
Number of blue stickers
= 1 u + 320
= 1 x 16 + 320
= 16 + 320
= 336
(b)
Number of green stickers
= 4 u
= 4 x 16
= 64
Answer(s): (a) 336; (b) 64