Adam has some blue stickers and green stickers.
If 400 blue stickers are removed, 90% of the stickers will be green stickers.
If 88 blue stickers are removed, 25% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 400 |
9 u |
27 u + 88 |
9 u |
Change |
- 400 |
No change |
- 88 |
No change |
After |
1x1 = 1 u |
9x1 = 9 u |
3x9 = 27 u |
1x9 = 9 u |
(a)
90% =
90100 =
91025% =
25100 =
14Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
910 =
110 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
14 =
34 The number of green stickers remains unchanged in both scenarios.
LCM of 9 and 1 = 9
1 u + 400 = 27 u + 88
27 u - 1 u = 400 - 88
26 u = 312
1 u = 312 ÷ 26 = 12
Number of blue stickers
= 1 u + 400
= 1 x 12 + 400
= 12 + 400
= 412
(b)
Number of green stickers
= 9 u
= 9 x 12
= 108
Answer(s): (a) 412; (b) 108