Adam has some green stickers and blue stickers.
If 276 green stickers are removed, 70% of the stickers will be blue stickers.
If 96 green stickers are removed, 40% of the stickers will be blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
6 u + 276 |
14 u |
21 u + 96 |
14 u |
Change |
- 276 |
No change |
- 96 |
No change |
After |
3x2 = 6 u |
7x2 = 14 u |
3x7 = 21 u |
2x7 = 14 u |
(a)
70% =
70100 =
71040% =
40100 =
25Scenario 1 Fraction of the stickers that are green in the end
= 1 -
710 =
310 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
25 =
35 The number of blue stickers remains unchanged in both scenarios.
LCM of 7 and 2 = 14
6 u + 276 = 21 u + 96
21 u - 6 u = 276 - 96
15 u = 180
1 u = 180 ÷ 15 = 12
Number of green stickers
= 6 u + 276
= 6 x 12 + 276
= 72 + 276
= 348
(b)
Number of blue stickers
= 14 u
= 14 x 12
= 168
Answer(s): (a) 348; (b) 168