Adam has some blue stickers and green stickers.
If 154 blue stickers are removed, 90% of the stickers will be green stickers.
If 196 blue stickers are added, 40% of the stickers will be green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
2 u + 154 |
18 u |
27 u - 196 |
18 u |
Change |
- 154 |
No change |
+ 196 |
No change |
After |
1x2 = 2 u |
9x2 = 18 u |
3x9 = 27 u |
2x9 = 18 u |
(a)
90% =
90100 =
91040% =
40100 =
25Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
910 =
110 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
25 =
35 The number of green stickers remains unchanged in both scenarios.
LCM of 9 and 2 = 18
27 u - 196 = 2 u + 154
27 u - 2 u = 154 + 196
25 u = 350
1 u = 350 ÷ 25 = 14
Number of blue stickers
= 2 u + 154
= 2 x 14 + 154
= 28 + 154
= 182
(b)
Number of green stickers
= 18 u
= 18 x 14
= 252
Answer(s): (a) 182; (b) 252