If Bryan gives Adam 271 stickers,
the number of stickers that Bryan will have is 15% of Adam's.
If Adam gives Bryan 9 stickers,
the number of stickers that Bryan will have is 50% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
9 u + 271 |
60 u - 271 |
23 u - 9 |
46 u + 9 |
Change |
- 271 |
+ 271 |
+ 9 |
- 9 |
After |
3x3 = 9 u |
20x3 = 60 u |
1x23 = 23 u |
2x23 = 46 u |
(a)
15% =
15100 =
320 50% =
50100 =
12 The totals in both scenarios are the same.
LCM of 23 and 3 = 69
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
23 u - 9 = 9 u + 271
23 u - 9 u = 271 + 9
14 u = 280
1 u = 280 ÷ 14 = 20
Number of stickers that Bryan has
= 9 u + 271
= 9 x 20 + 271
= 180 + 271
= 451
(b)
Number of stickers that Adam has
= 60 u - 271
= 60 x 20 - 271
= 1200 - 271
= 929
Answer(s): (a) 451; (b) 929