If Adam gives Bryan 41 stickers,
the number of stickers that Adam will have is 20% of Bryan's.
If Bryan gives Adam 19 stickers,
the number of stickers that Adam will have is 40% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
7 u + 41 |
35 u - 41 |
12 u - 19 |
30 u + 19 |
Change |
- 41 |
+ 41 |
+ 19 |
- 19 |
After |
1x7 = 7 u |
5x7 = 35 u |
2x6 = 12 u |
5x6 = 30 u |
(a)
20% =
20100 =
15 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 6 and 7 = 42
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
12 u - 19 = 7 u + 41
12 u - 7 u = 41 + 19
5 u = 60
1 u = 60 ÷ 5 = 12
Number of stickers that Adam has
= 7 u + 41
= 7 x 12 + 41
= 84 + 41
= 125
(b)
Number of stickers that Bryan has
= 35 u - 41
= 35 x 12 - 41
= 420 - 41
= 379
Answer(s): (a) 125; (b) 379