If Adam gives Bryan 13 stickers,
the number of stickers that Adam will have is 20% of Bryan's.
If Bryan gives Adam 6 stickers,
the number of stickers that Adam will have is 50% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
1 u + 13 |
5 u - 13 |
2 u - 6 |
4 u + 6 |
Change |
- 13 |
+ 13 |
+ 6 |
- 6 |
After |
1x1 = 1 u |
5x1 = 5 u |
1x2 = 2 u |
2x2 = 4 u |
(a)
20% =
20100 =
15 50% =
50100 =
12 The totals in both scenarios are the same.
LCM of 6 and 3 = 6
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
2 u - 6 = 1 u + 13
2 u - 1 u = 13 + 6
1 u = 19
1 u = 19 ÷ 1 = 19
Number of stickers that Adam has
= 1 u + 13
= 1 x 19 + 13
= 19 + 13
= 32
(b)
Number of stickers that Bryan has
= 5 u - 13
= 5 x 19 - 13
= 95 - 13
= 82
Answer(s): (a) 32; (b) 82