If Adam gives Bryan 57 stickers,
the number of stickers that Adam will have is 20% of Bryan's.
If Bryan gives Adam 18 stickers,
the number of stickers that Adam will have is 30% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
13 u + 57 |
65 u - 57 |
18 u - 18 |
60 u + 18 |
Change |
- 57 |
+ 57 |
+ 18 |
- 18 |
After |
1x13 = 13 u |
5x13 = 65 u |
3x6 = 18 u |
10x6 = 60 u |
(a)
20% =
20100 =
15 30% =
30100 =
310 The totals in both scenarios are the same.
LCM of 6 and 13 = 78
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
18 u - 18 = 13 u + 57
18 u - 13 u = 57 + 18
5 u = 75
1 u = 75 ÷ 5 = 15
Number of stickers that Adam has
= 13 u + 57
= 13 x 15 + 57
= 195 + 57
= 252
(b)
Number of stickers that Bryan has
= 65 u - 57
= 65 x 15 - 57
= 975 - 57
= 918
Answer(s): (a) 252; (b) 918