If Bryan gives Adam 47 stickers,
the number of stickers that Bryan will have is 20% of Adam's.
If Adam gives Bryan 18 stickers,
the number of stickers that Bryan will have is 40% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
7 u + 47 |
35 u - 47 |
12 u - 18 |
30 u + 18 |
Change |
- 47 |
+ 47 |
+ 18 |
- 18 |
After |
1x7 = 7 u |
5x7 = 35 u |
2x6 = 12 u |
5x6 = 30 u |
(a)
20% =
20100 =
15 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 6 and 7 = 42
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
12 u - 18 = 7 u + 47
12 u - 7 u = 47 + 18
5 u = 65
1 u = 65 ÷ 5 = 13
Number of stickers that Bryan has
= 7 u + 47
= 7 x 13 + 47
= 91 + 47
= 138
(b)
Number of stickers that Adam has
= 35 u - 47
= 35 x 13 - 47
= 455 - 47
= 408
Answer(s): (a) 138; (b) 408