If Adam gives Bryan 71 stickers,
the number of stickers that Adam will have is 30% of Bryan's.
If Bryan gives Adam 19 stickers,
the number of stickers that Adam will have is 40% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
21 u + 71 |
70 u - 71 |
26 u - 19 |
65 u + 19 |
Change |
- 71 |
+ 71 |
+ 19 |
- 19 |
After |
3x7 = 21 u |
10x7 = 70 u |
2x13 = 26 u |
5x13 = 65 u |
(a)
30% =
30100 =
310 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 13 and 7 = 91
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
26 u - 19 = 21 u + 71
26 u - 21 u = 71 + 19
5 u = 90
1 u = 90 ÷ 5 = 18
Number of stickers that Adam has
= 21 u + 71
= 21 x 18 + 71
= 378 + 71
= 449
(b)
Number of stickers that Bryan has
= 70 u - 71
= 70 x 18 - 71
= 1260 - 71
= 1189
Answer(s): (a) 449; (b) 1189