If Bryan gives Adam 41 stickers,
the number of stickers that Bryan will have is 25% of Adam's.
If Adam gives Bryan 10 stickers,
the number of stickers that Bryan will have is 40% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
7 u + 41 |
28 u - 41 |
10 u - 10 |
25 u + 10 |
Change |
- 41 |
+ 41 |
+ 10 |
- 10 |
After |
1x7 = 7 u |
4x7 = 28 u |
2x5 = 10 u |
5x5 = 25 u |
(a)
25% =
25100 =
14 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 5 and 7 = 35
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
10 u - 10 = 7 u + 41
10 u - 7 u = 41 + 10
3 u = 51
1 u = 51 ÷ 3 = 17
Number of stickers that Bryan has
= 7 u + 41
= 7 x 17 + 41
= 119 + 41
= 160
(b)
Number of stickers that Adam has
= 28 u - 41
= 28 x 17 - 41
= 476 - 41
= 435
Answer(s): (a) 160; (b) 435