If Bryan gives Adam 63 stickers,
the number of stickers that Bryan will have is 30% of Adam's.
If Adam gives Bryan 7 stickers,
the number of stickers that Bryan will have is 40% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
21 u + 63 |
70 u - 63 |
26 u - 7 |
65 u + 7 |
Change |
- 63 |
+ 63 |
+ 7 |
- 7 |
After |
3x7 = 21 u |
10x7 = 70 u |
2x13 = 26 u |
5x13 = 65 u |
(a)
30% =
30100 =
310 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 13 and 7 = 91
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
26 u - 7 = 21 u + 63
26 u - 21 u = 63 + 7
5 u = 70
1 u = 70 ÷ 5 = 14
Number of stickers that Bryan has
= 21 u + 63
= 21 x 14 + 63
= 294 + 63
= 357
(b)
Number of stickers that Adam has
= 70 u - 63
= 70 x 14 - 63
= 980 - 63
= 917
Answer(s): (a) 357; (b) 917