If Adam gives Bryan 61 stickers,
the number of stickers that Adam will have is 20% of Bryan's.
If Bryan gives Adam 9 stickers,
the number of stickers that Adam will have is 40% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
7 u + 61 |
35 u - 61 |
12 u - 9 |
30 u + 9 |
Change |
- 61 |
+ 61 |
+ 9 |
- 9 |
After |
1x7 = 7 u |
5x7 = 35 u |
2x6 = 12 u |
5x6 = 30 u |
(a)
20% =
20100 =
15 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 6 and 7 = 42
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
12 u - 9 = 7 u + 61
12 u - 7 u = 61 + 9
5 u = 70
1 u = 70 ÷ 5 = 14
Number of stickers that Adam has
= 7 u + 61
= 7 x 14 + 61
= 98 + 61
= 159
(b)
Number of stickers that Bryan has
= 35 u - 61
= 35 x 14 - 61
= 490 - 61
= 429
Answer(s): (a) 159; (b) 429