If Adam gives Bryan 31 stickers,
the number of stickers that Adam will have is 25% of Bryan's.
If Bryan gives Adam 8 stickers,
the number of stickers that Adam will have is 40% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
7 u + 31 |
28 u - 31 |
10 u - 8 |
25 u + 8 |
Change |
- 31 |
+ 31 |
+ 8 |
- 8 |
After |
1x7 = 7 u |
4x7 = 28 u |
2x5 = 10 u |
5x5 = 25 u |
(a)
25% =
25100 =
14 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 5 and 7 = 35
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
10 u - 8 = 7 u + 31
10 u - 7 u = 31 + 8
3 u = 39
1 u = 39 ÷ 3 = 13
Number of stickers that Adam has
= 7 u + 31
= 7 x 13 + 31
= 91 + 31
= 122
(b)
Number of stickers that Bryan has
= 28 u - 31
= 28 x 13 - 31
= 364 - 31
= 333
Answer(s): (a) 122; (b) 333