If Bryan gives Adam 64 stickers,
the number of stickers that Bryan will have is 20% of Adam's.
If Adam gives Bryan 11 stickers,
the number of stickers that Bryan will have is 40% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
7 u + 64 |
35 u - 64 |
12 u - 11 |
30 u + 11 |
Change |
- 64 |
+ 64 |
+ 11 |
- 11 |
After |
1x7 = 7 u |
5x7 = 35 u |
2x6 = 12 u |
5x6 = 30 u |
(a)
20% =
20100 =
15 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 6 and 7 = 42
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
12 u - 11 = 7 u + 64
12 u - 7 u = 64 + 11
5 u = 75
1 u = 75 ÷ 5 = 15
Number of stickers that Bryan has
= 7 u + 64
= 7 x 15 + 64
= 105 + 64
= 169
(b)
Number of stickers that Adam has
= 35 u - 64
= 35 x 15 - 64
= 525 - 64
= 461
Answer(s): (a) 169; (b) 461