If Bryan gives Adam 58 stickers,
the number of stickers that Bryan will have is 30% of Adam's.
If Adam gives Bryan 6 stickers,
the number of stickers that Bryan will have is 50% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
9 u + 58 |
30 u - 58 |
13 u - 6 |
26 u + 6 |
Change |
- 58 |
+ 58 |
+ 6 |
- 6 |
After |
3x3 = 9 u |
10x3 = 30 u |
1x13 = 13 u |
2x13 = 26 u |
(a)
30% =
30100 =
310 50% =
50100 =
12 The totals in both scenarios are the same.
LCM of 13 and 3 = 39
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
13 u - 6 = 9 u + 58
13 u - 9 u = 58 + 6
4 u = 64
1 u = 64 ÷ 4 = 16
Number of stickers that Bryan has
= 9 u + 58
= 9 x 16 + 58
= 144 + 58
= 202
(b)
Number of stickers that Adam has
= 30 u - 58
= 30 x 16 - 58
= 480 - 58
= 422
Answer(s): (a) 202; (b) 422