If Bryan gives Adam 41 stickers,
the number of stickers that Bryan will have is 30% of Adam's.
If Adam gives Bryan 19 stickers,
the number of stickers that Bryan will have is 40% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
21 u + 41 |
70 u - 41 |
26 u - 19 |
65 u + 19 |
Change |
- 41 |
+ 41 |
+ 19 |
- 19 |
After |
3x7 = 21 u |
10x7 = 70 u |
2x13 = 26 u |
5x13 = 65 u |
(a)
30% =
30100 =
310 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 13 and 7 = 91
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
26 u - 19 = 21 u + 41
26 u - 21 u = 41 + 19
5 u = 60
1 u = 60 ÷ 5 = 12
Number of stickers that Bryan has
= 21 u + 41
= 21 x 12 + 41
= 252 + 41
= 293
(b)
Number of stickers that Adam has
= 70 u - 41
= 70 x 12 - 41
= 840 - 41
= 799
Answer(s): (a) 293; (b) 799