If Adam gives Bryan 49 stickers,
the number of stickers that Adam will have is 30% of Bryan's.
If Bryan gives Adam 11 stickers,
the number of stickers that Adam will have is 40% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
21 u + 49 |
70 u - 49 |
26 u - 11 |
65 u + 11 |
Change |
- 49 |
+ 49 |
+ 11 |
- 11 |
After |
3x7 = 21 u |
10x7 = 70 u |
2x13 = 26 u |
5x13 = 65 u |
(a)
30% =
30100 =
310 40% =
40100 =
25 The totals in both scenarios are the same.
LCM of 13 and 7 = 91
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
26 u - 11 = 21 u + 49
26 u - 21 u = 49 + 11
5 u = 60
1 u = 60 ÷ 5 = 12
Number of stickers that Adam has
= 21 u + 49
= 21 x 12 + 49
= 252 + 49
= 301
(b)
Number of stickers that Bryan has
= 70 u - 49
= 70 x 12 - 49
= 840 - 49
= 791
Answer(s): (a) 301; (b) 791