If Adam gives Bryan 57 stickers,
the number of stickers that Adam will have is 30% of Bryan's.
If Bryan gives Adam 19 stickers,
the number of stickers that Adam will have is 50% of Bryan's.
- How many stickers does Adam have?
- How many stickers does Bryan have?
|
Scenario 1 |
Scenario 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
9 u + 57 |
30 u - 57 |
13 u - 19 |
26 u + 19 |
Change |
- 57 |
+ 57 |
+ 19 |
- 19 |
After |
3x3 = 9 u |
10x3 = 30 u |
1x13 = 13 u |
2x13 = 26 u |
(a)
30% =
30100 =
310 50% =
50100 =
12 The totals in both scenarios are the same.
LCM of 13 and 3 = 39
Amount that Adam has at first in Scenario 2 = Amount that Adam has at first in Scenario 1
13 u - 19 = 9 u + 57
13 u - 9 u = 57 + 19
4 u = 76
1 u = 76 ÷ 4 = 19
Number of stickers that Adam has
= 9 u + 57
= 9 x 19 + 57
= 171 + 57
= 228
(b)
Number of stickers that Bryan has
= 30 u - 57
= 30 x 19 - 57
= 570 - 57
= 513
Answer(s): (a) 228; (b) 513