If Bryan gives Adam 118 stickers,
the number of stickers that Bryan will have is 15% of Adam's.
If Adam gives Bryan 8 stickers,
the number of stickers that Bryan will have is 50% of Adam's.
- How many stickers does Bryan have?
- How many stickers does Adam have?
|
Scenario 1 |
Scenario 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
9 u + 118 |
60 u - 118 |
23 u - 8 |
46 u + 8 |
Change |
- 118 |
+ 118 |
+ 8 |
- 8 |
After |
3x3 = 9 u |
20x3 = 60 u |
1x23 = 23 u |
2x23 = 46 u |
(a)
15% =
15100 =
320 50% =
50100 =
12 The totals in both scenarios are the same.
LCM of 23 and 3 = 69
Amount that Bryan has at first in Scenario 2 = Amount that Bryan has at first in Scenario 1
23 u - 8 = 9 u + 118
23 u - 9 u = 118 + 8
14 u = 126
1 u = 126 ÷ 14 = 9
Number of stickers that Bryan has
= 9 u + 118
= 9 x 9 + 118
= 81 + 118
= 199
(b)
Number of stickers that Adam has
= 60 u - 118
= 60 x 9 - 118
= 540 - 118
= 422
Answer(s): (a) 199; (b) 422