Adam has some green stickers and red stickers.
If Adam receives another 125 red stickers,
the green stickers will be 20% as many as the red stickers.
If Adam receives another 86 green stickers,
the green stickers will be 80% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u |
5 u - 125 |
4 p - 86 |
5 p |
Change |
No change |
+ 125 |
+ 86 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u
Number of red stickers at first = 5 u - 125
Scenario 2 Number of green stickers at first = 4 p - 86
Number of red stickers at first = 5 p
1 u = 4 p - 86 --- (1)
5 u - 125 = 5 p --- (2)
(2)
÷ 51 u - 25 = 1 p
1 u = 1 p + 25 --- (3)
(1) = (3)
4 p - 86 = 1 p + 25
4 p - 1 p = 86 + 25
3 p = 111
1 p = 111 ÷ 3 = 37
Number of green stickers
= 4 p - 86
= 4 x 37 - 86
= 148 - 86
= 62
(b)
Number of red stickers
= 5 p
= 5 x 37
= 185
Answer(s): (a) 62; (b) 185