Adam has some blue stickers and green stickers.
If Adam receives another 270 green stickers,
the blue stickers will be 20% as many as the green stickers.
If Adam receives another 72 blue stickers,
the blue stickers will be 80% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u |
5 u - 270 |
4 p - 72 |
5 p |
Change |
No change |
+ 270 |
+ 72 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u
Number of green stickers at first = 5 u - 270
Scenario 2 Number of blue stickers at first = 4 p - 72
Number of green stickers at first = 5 p
1 u = 4 p - 72 --- (1)
5 u - 270 = 5 p --- (2)
(2)
÷ 51 u - 54 = 1 p
1 u = 1 p + 54 --- (3)
(1) = (3)
4 p - 72 = 1 p + 54
4 p - 1 p = 72 + 54
3 p = 126
1 p = 126 ÷ 3 = 42
Number of blue stickers
= 4 p - 72
= 4 x 42 - 72
= 168 - 72
= 96
(b)
Number of green stickers
= 5 p
= 5 x 42
= 210
Answer(s): (a) 96; (b) 210