Adam has some red stickers and blue stickers.
If Adam receives another 235 blue stickers,
the red stickers will be 20% as many as the blue stickers.
If Adam receives another 22 red stickers,
the red stickers will be 80% as many as the blue stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u |
5 u - 235 |
4 p - 22 |
5 p |
Change |
No change |
+ 235 |
+ 22 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u
Number of blue stickers at first = 5 u - 235
Scenario 2 Number of red stickers at first = 4 p - 22
Number of blue stickers at first = 5 p
1 u = 4 p - 22 --- (1)
5 u - 235 = 5 p --- (2)
(2)
÷ 51 u - 47 = 1 p
1 u = 1 p + 47 --- (3)
(1) = (3)
4 p - 22 = 1 p + 47
4 p - 1 p = 22 + 47
3 p = 69
1 p = 69 ÷ 3 = 23
Number of red stickers
= 4 p - 22
= 4 x 23 - 22
= 92 - 22
= 70
(b)
Number of blue stickers
= 5 p
= 5 x 23
= 115
Answer(s): (a) 70; (b) 115