Adam has some red stickers and green stickers.
If Adam receives another 85 green stickers,
the red stickers will be 20% as many as the green stickers.
If Adam receives another 25 red stickers,
the red stickers will be 80% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u |
5 u - 85 |
4 p - 25 |
5 p |
Change |
No change |
+ 85 |
+ 25 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u
Number of green stickers at first = 5 u - 85
Scenario 2 Number of red stickers at first = 4 p - 25
Number of green stickers at first = 5 p
1 u = 4 p - 25 --- (1)
5 u - 85 = 5 p --- (2)
(2)
÷ 51 u - 17 = 1 p
1 u = 1 p + 17 --- (3)
(1) = (3)
4 p - 25 = 1 p + 17
4 p - 1 p = 25 + 17
3 p = 42
1 p = 42 ÷ 3 = 14
Number of red stickers
= 4 p - 25
= 4 x 14 - 25
= 56 - 25
= 31
(b)
Number of green stickers
= 5 p
= 5 x 14
= 70
Answer(s): (a) 31; (b) 70