Adam has some red stickers and green stickers.
If Adam receives another 705 green stickers,
the red stickers will be 20% as many as the green stickers.
If Adam receives another 57 red stickers,
the red stickers will be 80% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u |
5 u - 705 |
4 p - 57 |
5 p |
Change |
No change |
+ 705 |
+ 57 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u
Number of green stickers at first = 5 u - 705
Scenario 2 Number of red stickers at first = 4 p - 57
Number of green stickers at first = 5 p
1 u = 4 p - 57 --- (1)
5 u - 705 = 5 p --- (2)
(2)
÷ 51 u - 141 = 1 p
1 u = 1 p + 141 --- (3)
(1) = (3)
4 p - 57 = 1 p + 141
4 p - 1 p = 57 + 141
3 p = 198
1 p = 198 ÷ 3 = 66
Number of red stickers
= 4 p - 57
= 4 x 66 - 57
= 264 - 57
= 207
(b)
Number of green stickers
= 5 p
= 5 x 66
= 330
Answer(s): (a) 207; (b) 330