Adam has some blue stickers and green stickers.
If Adam receives another 160 green stickers,
the blue stickers will be 20% as many as the green stickers.
If Adam receives another 85 blue stickers,
the blue stickers will be 80% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u |
5 u - 160 |
4 p - 85 |
5 p |
Change |
No change |
+ 160 |
+ 85 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u
Number of green stickers at first = 5 u - 160
Scenario 2 Number of blue stickers at first = 4 p - 85
Number of green stickers at first = 5 p
1 u = 4 p - 85 --- (1)
5 u - 160 = 5 p --- (2)
(2)
÷ 51 u - 32 = 1 p
1 u = 1 p + 32 --- (3)
(1) = (3)
4 p - 85 = 1 p + 32
4 p - 1 p = 85 + 32
3 p = 117
1 p = 117 ÷ 3 = 39
Number of blue stickers
= 4 p - 85
= 4 x 39 - 85
= 156 - 85
= 71
(b)
Number of green stickers
= 5 p
= 5 x 39
= 195
Answer(s): (a) 71; (b) 195