Adam has some blue stickers and green stickers.
If Adam receives another 85 green stickers,
the blue stickers will be 20% as many as the green stickers.
If Adam receives another 22 blue stickers,
the blue stickers will be 80% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u |
5 u - 85 |
4 p - 22 |
5 p |
Change |
No change |
+ 85 |
+ 22 |
No change |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u
Number of green stickers at first = 5 u - 85
Scenario 2 Number of blue stickers at first = 4 p - 22
Number of green stickers at first = 5 p
1 u = 4 p - 22 --- (1)
5 u - 85 = 5 p --- (2)
(2)
÷ 51 u - 17 = 1 p
1 u = 1 p + 17 --- (3)
(1) = (3)
4 p - 22 = 1 p + 17
4 p - 1 p = 22 + 17
3 p = 39
1 p = 39 ÷ 3 = 13
Number of blue stickers
= 4 p - 22
= 4 x 13 - 22
= 52 - 22
= 30
(b)
Number of green stickers
= 5 p
= 5 x 13
= 65
Answer(s): (a) 30; (b) 65