Adam has some green stickers and red stickers.
If Adam receives another 32 red stickers,
the green stickers will be 25% as many as the red stickers.
If Adam receives another 14 green stickers,
the green stickers will be 75% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u |
4 u - 32 |
3 p - 14 |
4 p |
Change |
No change |
+ 32 |
+ 14 |
No change |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u
Number of red stickers at first = 4 u - 32
Scenario 2 Number of green stickers at first = 3 p - 14
Number of red stickers at first = 4 p
1 u = 3 p - 14 --- (1)
4 u - 32 = 4 p --- (2)
(2)
÷ 41 u - 8 = 1 p
1 u = 1 p + 8 --- (3)
(1) = (3)
3 p - 14 = 1 p + 8
3 p - 1 p = 14 + 8
2 p = 22
1 p = 22 ÷ 2 = 11
Number of green stickers
= 3 p - 14
= 3 x 11 - 14
= 33 - 14
= 19
(b)
Number of red stickers
= 4 p
= 4 x 11
= 44
Answer(s): (a) 19; (b) 44