Adam has some red stickers and blue stickers.
If Adam receives another 88 blue stickers,
the red stickers will be 25% as many as the blue stickers.
If Adam receives another 92 red stickers,
the red stickers will be 75% as many as the blue stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u |
4 u - 88 |
3 p - 92 |
4 p |
Change |
No change |
+ 88 |
+ 92 |
No change |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u
Number of blue stickers at first = 4 u - 88
Scenario 2 Number of red stickers at first = 3 p - 92
Number of blue stickers at first = 4 p
1 u = 3 p - 92 --- (1)
4 u - 88 = 4 p --- (2)
(2)
÷ 41 u - 22 = 1 p
1 u = 1 p + 22 --- (3)
(1) = (3)
3 p - 92 = 1 p + 22
3 p - 1 p = 92 + 22
2 p = 114
1 p = 114 ÷ 2 = 57
Number of red stickers
= 3 p - 92
= 3 x 57 - 92
= 171 - 92
= 79
(b)
Number of blue stickers
= 4 p
= 4 x 57
= 228
Answer(s): (a) 79; (b) 228