Adam has some blue stickers and green stickers.
If Adam gives away 38 blue stickers,
the blue stickers will be 10% as many as the green stickers.
If Adam gives away 145 green stickers,
the blue stickers will be 80% as many as the green stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 38 |
10 u |
4 p |
5 p + 145 |
Change |
- 38 |
No change |
No change |
- 145 |
After |
1 u |
10 u |
4 p |
5 p |
(a)
10% =
10100 =
110 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u + 38
Number of green stickers at first = 10 u
Scenario 2 Number of blue stickers at first = 4 p
Number of green stickers at first = 5 p + 145
1 u + 38 = 4 p --- (1)
10 u = 5 p + 145 --- (2)
(1)
x 10 10 u + 380 = 40 p
10 u = 40 p - 380 --- (3)
(3) = (2)
40 p - 380 = 5 p + 145
40 p - 5 p = 380 + 145
35 p = 525
1 p = 525 ÷ 35 = 15
Number of blue stickers
= 4 p
= 4 x 15
= 60
(b)
Number of green stickers at first
= 5 p + 145
= 5 x 15 + 145
= 75 + 145
= 220
Answer(s): (a) 60; (b) 220