Adam has some red stickers and green stickers.
If Adam gives away 11 red stickers,
the red stickers will be 10% as many as the green stickers.
If Adam gives away 55 green stickers,
the red stickers will be 40% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 11 |
10 u |
2 p |
5 p + 55 |
Change |
- 11 |
No change |
No change |
- 55 |
After |
1 u |
10 u |
2 p |
5 p |
(a)
10% =
10100 =
110 40% =
40100 =
25 Scenario 1 Number of red stickers at first = 1 u + 11
Number of green stickers at first = 10 u
Scenario 2 Number of red stickers at first = 2 p
Number of green stickers at first = 5 p + 55
1 u + 11 = 2 p --- (1)
10 u = 5 p + 55 --- (2)
(1)
x 10 10 u + 110 = 20 p
10 u = 20 p - 110 --- (3)
(3) = (2)
20 p - 110 = 5 p + 55
20 p - 5 p = 110 + 55
15 p = 165
1 p = 165 ÷ 15 = 11
Number of red stickers
= 2 p
= 2 x 11
= 22
(b)
Number of green stickers at first
= 5 p + 55
= 5 x 11 + 55
= 55 + 55
= 110
Answer(s): (a) 22; (b) 110