Adam has some green stickers and red stickers.
If Adam gives away 42 green stickers,
the green stickers will be 25% as many as the red stickers.
If Adam gives away 8 red stickers,
the green stickers will be 80% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 42 |
4 u |
4 p |
5 p + 8 |
Change |
- 42 |
No change |
No change |
- 8 |
After |
1 u |
4 u |
4 p |
5 p |
(a)
25% =
25100 =
14 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u + 42
Number of red stickers at first = 4 u
Scenario 2 Number of green stickers at first = 4 p
Number of red stickers at first = 5 p + 8
1 u + 42 = 4 p --- (1)
4 u = 5 p + 8 --- (2)
(1)
x 4 4 u + 168 = 16 p
4 u = 16 p - 168 --- (3)
(3) = (2)
16 p - 168 = 5 p + 8
16 p - 5 p = 168 + 8
11 p = 176
1 p = 176 ÷ 11 = 16
Number of green stickers
= 4 p
= 4 x 16
= 64
(b)
Number of red stickers at first
= 5 p + 8
= 5 x 16 + 8
= 80 + 8
= 88
Answer(s): (a) 64; (b) 88