Adam has some red stickers and green stickers.
If Adam gives away 27 red stickers,
the red stickers will be 20% as many as the green stickers.
If Adam gives away 225 green stickers,
the red stickers will be 80% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 27 |
5 u |
4 p |
5 p + 225 |
Change |
- 27 |
No change |
No change |
- 225 |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u + 27
Number of green stickers at first = 5 u
Scenario 2 Number of red stickers at first = 4 p
Number of green stickers at first = 5 p + 225
1 u + 27 = 4 p --- (1)
5 u = 5 p + 225 --- (2)
(1)
x 5 5 u + 135 = 20 p
5 u = 20 p - 135 --- (3)
(3) = (2)
20 p - 135 = 5 p + 225
20 p - 5 p = 135 + 225
15 p = 360
1 p = 360 ÷ 15 = 24
Number of red stickers
= 4 p
= 4 x 24
= 96
(b)
Number of green stickers at first
= 5 p + 225
= 5 x 24 + 225
= 120 + 225
= 345
Answer(s): (a) 96; (b) 345