Adam has some green stickers and red stickers.
If Adam gives away 30 green stickers,
the green stickers will be 10% as many as the red stickers.
If Adam gives away 155 red stickers,
the green stickers will be 80% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 30 |
10 u |
4 p |
5 p + 155 |
Change |
- 30 |
No change |
No change |
- 155 |
After |
1 u |
10 u |
4 p |
5 p |
(a)
10% =
10100 =
110 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u + 30
Number of red stickers at first = 10 u
Scenario 2 Number of green stickers at first = 4 p
Number of red stickers at first = 5 p + 155
1 u + 30 = 4 p --- (1)
10 u = 5 p + 155 --- (2)
(1)
x 10 10 u + 300 = 40 p
10 u = 40 p - 300 --- (3)
(3) = (2)
40 p - 300 = 5 p + 155
40 p - 5 p = 300 + 155
35 p = 455
1 p = 455 ÷ 35 = 13
Number of green stickers
= 4 p
= 4 x 13
= 52
(b)
Number of red stickers at first
= 5 p + 155
= 5 x 13 + 155
= 65 + 155
= 220
Answer(s): (a) 52; (b) 220