Adam has some red stickers and blue stickers.
If Adam gives away 26 red stickers,
the red stickers will be 20% as many as the blue stickers.
If Adam gives away 57 blue stickers,
the red stickers will be 75% as many as the blue stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u + 26 |
5 u |
3 p |
4 p + 57 |
Change |
- 26 |
No change |
No change |
- 57 |
After |
1 u |
5 u |
3 p |
4 p |
(a)
20% =
20100 =
15 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u + 26
Number of blue stickers at first = 5 u
Scenario 2 Number of red stickers at first = 3 p
Number of blue stickers at first = 4 p + 57
1 u + 26 = 3 p --- (1)
5 u = 4 p + 57 --- (2)
(1)
x 5 5 u + 130 = 15 p
5 u = 15 p - 130 --- (3)
(3) = (2)
15 p - 130 = 4 p + 57
15 p - 4 p = 130 + 57
11 p = 187
1 p = 187 ÷ 11 = 17
Number of red stickers
= 3 p
= 3 x 17
= 51
(b)
Number of blue stickers at first
= 4 p + 57
= 4 x 17 + 57
= 68 + 57
= 125
Answer(s): (a) 51; (b) 125