Adam has some green stickers and blue stickers.
If Adam gives away 14 green stickers,
the green stickers will be 20% as many as the blue stickers.
If Adam gives away 45 blue stickers,
the green stickers will be 40% as many as the blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 14 |
5 u |
2 p |
5 p + 45 |
Change |
- 14 |
No change |
No change |
- 45 |
After |
1 u |
5 u |
2 p |
5 p |
(a)
20% =
20100 =
15 40% =
40100 =
25 Scenario 1 Number of green stickers at first = 1 u + 14
Number of blue stickers at first = 5 u
Scenario 2 Number of green stickers at first = 2 p
Number of blue stickers at first = 5 p + 45
1 u + 14 = 2 p --- (1)
5 u = 5 p + 45 --- (2)
(1)
x 5 5 u + 70 = 10 p
5 u = 10 p - 70 --- (3)
(3) = (2)
10 p - 70 = 5 p + 45
10 p - 5 p = 70 + 45
5 p = 115
1 p = 115 ÷ 5 = 23
Number of green stickers
= 2 p
= 2 x 23
= 46
(b)
Number of blue stickers at first
= 5 p + 45
= 5 x 23 + 45
= 115 + 45
= 160
Answer(s): (a) 46; (b) 160