Adam has some green stickers and red stickers.
If Adam gives away 11 green stickers,
the green stickers will be 20% as many as the red stickers.
If Adam gives away 40 red stickers,
the green stickers will be 40% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 11 |
5 u |
2 p |
5 p + 40 |
Change |
- 11 |
No change |
No change |
- 40 |
After |
1 u |
5 u |
2 p |
5 p |
(a)
20% =
20100 =
15 40% =
40100 =
25 Scenario 1 Number of green stickers at first = 1 u + 11
Number of red stickers at first = 5 u
Scenario 2 Number of green stickers at first = 2 p
Number of red stickers at first = 5 p + 40
1 u + 11 = 2 p --- (1)
5 u = 5 p + 40 --- (2)
(1)
x 5 5 u + 55 = 10 p
5 u = 10 p - 55 --- (3)
(3) = (2)
10 p - 55 = 5 p + 40
10 p - 5 p = 55 + 40
5 p = 95
1 p = 95 ÷ 5 = 19
Number of green stickers
= 2 p
= 2 x 19
= 38
(b)
Number of red stickers at first
= 5 p + 40
= 5 x 19 + 40
= 95 + 40
= 135
Answer(s): (a) 38; (b) 135