Adam has some blue stickers and red stickers.
If Adam gives away 29 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 16 red stickers,
the blue stickers will be 80% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Red |
Blue |
Red |
Before |
1 u + 29 |
4 u |
4 p |
5 p + 16 |
Change |
- 29 |
No change |
No change |
- 16 |
After |
1 u |
4 u |
4 p |
5 p |
(a)
25% =
25100 =
14 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u + 29
Number of red stickers at first = 4 u
Scenario 2 Number of blue stickers at first = 4 p
Number of red stickers at first = 5 p + 16
1 u + 29 = 4 p --- (1)
4 u = 5 p + 16 --- (2)
(1)
x 4 4 u + 116 = 16 p
4 u = 16 p - 116 --- (3)
(3) = (2)
16 p - 116 = 5 p + 16
16 p - 5 p = 116 + 16
11 p = 132
1 p = 132 ÷ 11 = 12
Number of blue stickers
= 4 p
= 4 x 12
= 48
(b)
Number of red stickers at first
= 5 p + 16
= 5 x 12 + 16
= 60 + 16
= 76
Answer(s): (a) 48; (b) 76