Adam has some red stickers and green stickers.
If Adam gives away 46 red stickers,
the red stickers will be 10% as many as the green stickers.
If Adam gives away 275 green stickers,
the red stickers will be 80% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 46 |
10 u |
4 p |
5 p + 275 |
Change |
- 46 |
No change |
No change |
- 275 |
After |
1 u |
10 u |
4 p |
5 p |
(a)
10% =
10100 =
110 80% =
80100 =
45 Scenario 1 Number of red stickers at first = 1 u + 46
Number of green stickers at first = 10 u
Scenario 2 Number of red stickers at first = 4 p
Number of green stickers at first = 5 p + 275
1 u + 46 = 4 p --- (1)
10 u = 5 p + 275 --- (2)
(1)
x 10 10 u + 460 = 40 p
10 u = 40 p - 460 --- (3)
(3) = (2)
40 p - 460 = 5 p + 275
40 p - 5 p = 460 + 275
35 p = 735
1 p = 735 ÷ 35 = 21
Number of red stickers
= 4 p
= 4 x 21
= 84
(b)
Number of green stickers at first
= 5 p + 275
= 5 x 21 + 275
= 105 + 275
= 380
Answer(s): (a) 84; (b) 380