Adam has some blue stickers and red stickers.
If Adam gives away 36 blue stickers,
the blue stickers will be 25% as many as the red stickers.
If Adam gives away 21 red stickers,
the blue stickers will be 80% as many as the red stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Red |
Blue |
Red |
Before |
1 u + 36 |
4 u |
4 p |
5 p + 21 |
Change |
- 36 |
No change |
No change |
- 21 |
After |
1 u |
4 u |
4 p |
5 p |
(a)
25% =
25100 =
14 80% =
80100 =
45 Scenario 1 Number of blue stickers at first = 1 u + 36
Number of red stickers at first = 4 u
Scenario 2 Number of blue stickers at first = 4 p
Number of red stickers at first = 5 p + 21
1 u + 36 = 4 p --- (1)
4 u = 5 p + 21 --- (2)
(1)
x 4 4 u + 144 = 16 p
4 u = 16 p - 144 --- (3)
(3) = (2)
16 p - 144 = 5 p + 21
16 p - 5 p = 144 + 21
11 p = 165
1 p = 165 ÷ 11 = 15
Number of blue stickers
= 4 p
= 4 x 15
= 60
(b)
Number of red stickers at first
= 5 p + 21
= 5 x 15 + 21
= 75 + 21
= 96
Answer(s): (a) 60; (b) 96