Adam has some red stickers and green stickers.
If Adam gives away 14 red stickers,
the red stickers will be 25% as many as the green stickers.
If Adam gives away 64 green stickers,
the red stickers will be 75% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 14 |
4 u |
3 p |
4 p + 64 |
Change |
- 14 |
No change |
No change |
- 64 |
After |
1 u |
4 u |
3 p |
4 p |
(a)
25% =
25100 =
14 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u + 14
Number of green stickers at first = 4 u
Scenario 2 Number of red stickers at first = 3 p
Number of green stickers at first = 4 p + 64
1 u + 14 = 3 p --- (1)
4 u = 4 p + 64 --- (2)
(1)
x 4 4 u + 56 = 12 p
4 u = 12 p - 56 --- (3)
(3) = (2)
12 p - 56 = 4 p + 64
12 p - 4 p = 56 + 64
8 p = 120
1 p = 120 ÷ 8 = 15
Number of red stickers
= 3 p
= 3 x 15
= 45
(b)
Number of green stickers at first
= 4 p + 64
= 4 x 15 + 64
= 60 + 64
= 124
Answer(s): (a) 45; (b) 124