Adam has some green stickers and blue stickers.
If Adam gives away 11 green stickers,
the green stickers will be 20% as many as the blue stickers.
If Adam gives away 77 blue stickers,
the green stickers will be 75% as many as the blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 11 |
5 u |
3 p |
4 p + 77 |
Change |
- 11 |
No change |
No change |
- 77 |
After |
1 u |
5 u |
3 p |
4 p |
(a)
20% =
20100 =
15 75% =
75100 =
34 Scenario 1 Number of green stickers at first = 1 u + 11
Number of blue stickers at first = 5 u
Scenario 2 Number of green stickers at first = 3 p
Number of blue stickers at first = 4 p + 77
1 u + 11 = 3 p --- (1)
5 u = 4 p + 77 --- (2)
(1)
x 5 5 u + 55 = 15 p
5 u = 15 p - 55 --- (3)
(3) = (2)
15 p - 55 = 4 p + 77
15 p - 4 p = 55 + 77
11 p = 132
1 p = 132 ÷ 11 = 12
Number of green stickers
= 3 p
= 3 x 12
= 36
(b)
Number of blue stickers at first
= 4 p + 77
= 4 x 12 + 77
= 48 + 77
= 125
Answer(s): (a) 36; (b) 125