Adam has some red stickers and blue stickers.
If Adam gives away 21 red stickers,
the red stickers will be 10% as many as the blue stickers.
If Adam gives away 362 blue stickers,
the red stickers will be 75% as many as the blue stickers.

1. How many red stickers are there? 
2. How many blue stickers are there? 

	Scenario 1		Scenario 2
	Red	Blue	Red	Blue
Before	1 u + 21	10 u	3 p	4 p + 362
Change	- 21	No change	No change	- 362
After	1 u	10 u	3 p	4 p

(a)
10% = ¹⁰₁₀₀ = ¹₁₀
75% = ⁷⁵₁₀₀ = ³₄

Scenario 1
Number of red stickers at first = 1 u + 21
Number of blue stickers at first = 10 u

Scenario 2
Number of red stickers at first = 3 p
Number of blue stickers at first = 4 p + 362

1 u + 21 = 3 p --- (1)
10 u = 4 p + 362 --- (2)

(1) _{x 10}
10 u + 210 = 30 p
10 u = 30 p - 210 --- (3)

(3) = (2)
30 p - 210 = 4 p + 362
30 p - 4 p = 210 + 362
26 p = 572

1 p = 572 ÷ 26 = 22

Number of red stickers
= 3 p
= 3 x 22
= 66

(b)
Number of blue stickers at first
= 4 p + 362
= 4 x 22 + 362
= 88 + 362
= 450

Answer(s): (a) 66; (b) 450