Adam has some red stickers and green stickers.
If Adam gives away 15 red stickers,
the red stickers will be 10% as many as the green stickers.
If Adam gives away 195 green stickers,
the red stickers will be 40% as many as the green stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 15 |
10 u |
2 p |
5 p + 195 |
Change |
- 15 |
No change |
No change |
- 195 |
After |
1 u |
10 u |
2 p |
5 p |
(a)
10% =
10100 =
110 40% =
40100 =
25 Scenario 1 Number of red stickers at first = 1 u + 15
Number of green stickers at first = 10 u
Scenario 2 Number of red stickers at first = 2 p
Number of green stickers at first = 5 p + 195
1 u + 15 = 2 p --- (1)
10 u = 5 p + 195 --- (2)
(1)
x 10 10 u + 150 = 20 p
10 u = 20 p - 150 --- (3)
(3) = (2)
20 p - 150 = 5 p + 195
20 p - 5 p = 150 + 195
15 p = 345
1 p = 345 ÷ 15 = 23
Number of red stickers
= 2 p
= 2 x 23
= 46
(b)
Number of green stickers at first
= 5 p + 195
= 5 x 23 + 195
= 115 + 195
= 310
Answer(s): (a) 46; (b) 310