Adam has some red stickers and blue stickers.
If Adam gives away 42 red stickers,
the red stickers will be 10% as many as the blue stickers.
If Adam gives away 204 blue stickers,
the red stickers will be 75% as many as the blue stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u + 42 |
10 u |
3 p |
4 p + 204 |
Change |
- 42 |
No change |
No change |
- 204 |
After |
1 u |
10 u |
3 p |
4 p |
(a)
10% =
10100 =
110 75% =
75100 =
34 Scenario 1 Number of red stickers at first = 1 u + 42
Number of blue stickers at first = 10 u
Scenario 2 Number of red stickers at first = 3 p
Number of blue stickers at first = 4 p + 204
1 u + 42 = 3 p --- (1)
10 u = 4 p + 204 --- (2)
(1)
x 10 10 u + 420 = 30 p
10 u = 30 p - 420 --- (3)
(3) = (2)
30 p - 420 = 4 p + 204
30 p - 4 p = 420 + 204
26 p = 624
1 p = 624 ÷ 26 = 24
Number of red stickers
= 3 p
= 3 x 24
= 72
(b)
Number of blue stickers at first
= 4 p + 204
= 4 x 24 + 204
= 96 + 204
= 300
Answer(s): (a) 72; (b) 300