Adam has some green stickers and blue stickers.
If Adam gives away 29 green stickers,
the green stickers will be 20% as many as the blue stickers.
If Adam gives away 260 blue stickers,
the green stickers will be 80% as many as the blue stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 29 |
5 u |
4 p |
5 p + 260 |
Change |
- 29 |
No change |
No change |
- 260 |
After |
1 u |
5 u |
4 p |
5 p |
(a)
20% =
20100 =
15 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u + 29
Number of blue stickers at first = 5 u
Scenario 2 Number of green stickers at first = 4 p
Number of blue stickers at first = 5 p + 260
1 u + 29 = 4 p --- (1)
5 u = 5 p + 260 --- (2)
(1)
x 5 5 u + 145 = 20 p
5 u = 20 p - 145 --- (3)
(3) = (2)
20 p - 145 = 5 p + 260
20 p - 5 p = 145 + 260
15 p = 405
1 p = 405 ÷ 15 = 27
Number of green stickers
= 4 p
= 4 x 27
= 108
(b)
Number of blue stickers at first
= 5 p + 260
= 5 x 27 + 260
= 135 + 260
= 395
Answer(s): (a) 108; (b) 395