Adam has some green stickers and red stickers.
If Adam gives away 15 green stickers,
the green stickers will be 10% as many as the red stickers.
If Adam gives away 550 red stickers,
the green stickers will be 80% as many as the red stickers.
- How many green stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Red |
Green |
Red |
Before |
1 u + 15 |
10 u |
4 p |
5 p + 550 |
Change |
- 15 |
No change |
No change |
- 550 |
After |
1 u |
10 u |
4 p |
5 p |
(a)
10% =
10100 =
110 80% =
80100 =
45 Scenario 1 Number of green stickers at first = 1 u + 15
Number of red stickers at first = 10 u
Scenario 2 Number of green stickers at first = 4 p
Number of red stickers at first = 5 p + 550
1 u + 15 = 4 p --- (1)
10 u = 5 p + 550 --- (2)
(1)
x 10 10 u + 150 = 40 p
10 u = 40 p - 150 --- (3)
(3) = (2)
40 p - 150 = 5 p + 550
40 p - 5 p = 150 + 550
35 p = 700
1 p = 700 ÷ 35 = 20
Number of green stickers
= 4 p
= 4 x 20
= 80
(b)
Number of red stickers at first
= 5 p + 550
= 5 x 20 + 550
= 100 + 550
= 650
Answer(s): (a) 80; (b) 650